Question

Zeros of quadratic polynomial p (x) = 2x^2-81 are

Answer 1

★GIVEN:-

$\implies \: p(x) = 2x {}^{2} - 81$

★find:-

given polynomial zeros

zeros

find polynomial zeroes to first polynomial equal to zero

$\implies \: 2x {}^{2} - 81 = 0 \\ \\ \implies \: 2x {}^{2} = 81 \\ \\ \implies \: x {}^{2} = \frac{81}{2} \\ \\ \implies \: x = ±\sqrt{ \frac{81}{2} } \\ \\ \implies \: x = ± \frac{ \: \: \: \: 9}{ \sqrt{2} }$

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