Question

Zeros of the equation p(x)=x²+5x+4

Answer 1

Answer:

$\huge\mathfrak{\underline{\pink{\purple{heya\:mate♡}}}}$

${\bf{\red{given=>p(x) =x{^2}+5x+4}}}$

${\huge{\mathfrak{\bf{\orange{explanation}}}}}$

${\bf{\blue{ x{^2}+5x+4}}}$

${\bf{\green{x{^2}+(4+1) x+4}}}$

${\bf{\purple{x{^2}+4x+x+4}}}$

${\bf{\pink{x(x+4) +1(x+4)}}}$

${\bf{\blue{(x+1) (x+4)}}}$

${\bf{\orange{x=-1\:and\:x = -4}}}$

Answer 2

Answer:

x² + x+ 4x + 4x

x ( x +1 ) + 4 ( x + 1)

( x + 4 ) ( x + 1)

x = -4 or x= -1