Zeros of the polynomial 2x^(2)-16 : (a) 2 (b) 8 (c) +-2 sqrt(2) +-sqrt(2)
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Answered by
0
Answer:
c) ±2√2
Step-by-step explanation:
p(x)=0
2x^2 - 16 = 0
(√2x-4)(√2x+4)=0
x=±4/√2
If we rationalise...
x=±2√2
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Answered by
0
Answer:
2x²-16 = 0
=> 2( x²- 8 ) = 0
=> x² - 8 = 0
=> x² = 8
=> x = √8
=> x = 2√2
Therefore, Zeros of the polynomial is 2√2.
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