Question

Zeros of the polynomial p(x)=(x-2)^2-(x+2)^2 are *

2, -2

2x

0, -2

0

​

Answer 1

Step-by-step explanation:

$p(x) = (x - 2)^{2} - {(x + 2)}^{2} = 0$

or,

$4 \times 2 \times x = 0$

or,

$8x = 0$

or,

$x = 0$