Question

Zeros of the polynomial x^2-8

Answer 1

Answer:

4 and -4

Step-by-step explanation:

x^2+0x-8

x^2+4x-4x-8

x(x+4)-4(x+4)

(x+4)(x-4)

Therefore, the two zeroes,

x+4=0

x=-4 Ans

x-4=0

x=4 Ans

Answer 2

Answer:

$\sqrt{-8}$

Step-by-step explanation:

The question asks you to find the zeroes of the polynomial.

Let p(x)= x^2-8

p(x)= 0 (To find the zero of the polynomial

x^2= -8

x= $\sqrt{-8}$