Question

zeros of the quadratic polynomial 3x square + 11 x minus 6 is​

Answer 1

Method 1 :-

By splitting middle term

$\sf \implies {3x}^{2} + 9x + 2x + 6 = 0 \\ \\\sf \implies3x(x + 3) + 2(x + 3) = 0\\ \\ \sf \implies(x + 3)(3x + 2) = 0 \\ \\ \sf \implies x + 3 = 0 \\ \\ \implies\boxed{ \boxed{ \sf x = - 3}} \\ \\ \sf \implies3x + 2 = 0 \\ \\ \implies\boxed{ \boxed{ \sf x = - \frac{2}{3}}}$

Method 2 :

By using quadratic formula

$\large \implies\boxed{\boxed{ \sf \green{x =\frac{ - b \pm \sqrt{ {b}^{2} - 4ab } }{2a}}}}$

Here

• a = 3
• b = 11
• c =6

Substitute values in formula

$\sf \implies x = \frac{ - 11 \pm \sqrt{ {11}^{2} - 4 \times 3 \times 6 } }{2 \times 3} \\ \\ \sf \implies x = \frac{ - 11 \pm \sqrt{121 - 72} }{6} \\ \\\sf \implies x = \frac{ -11 \pm \sqrt{49} }{6} \\ \\ \sf \implies x = \frac{ - 11 \pm 7 }{6} \\ \\\sf \implies x = \frac{ - 11 + 7 }{6} \\ \\\implies \boxed{\boxed{ \sf x = - \frac{2}{3}}} \\ \\ \sf \implies x = \frac{ - 11 - 7 }{6} \\ \\\implies\boxed{ \boxed{ \sf x = - 3}}$

Answer 2

Answer:

Hope it helps you.......