zeros of the quadratic polynomial X square + (A + 1 )X + B are 2 and -3 then find the value of a and b
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The discriminant of the polynomial will be equal to zero if the zeroea are equal.
b^2-4ac = 0 [When roots are equal & real]
[-(k+2)]^2-4(k+1)= 0
k^2+4+4k-4k-4=0
k=0
manish265445:
this is wrong answer
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