Question

zeros of x cube + 64 is equal to zero​

Answer 1

Answer:

Step-by-step explanation:

x^3+64

=(x)^3+(4)^3

[(x^3+y^3)=(x+y)(x^2-xy+y^2)]

=(x+4)(x^2-4x+16)

zeroes of the polynomial = -4,4+$\sqrt{-48$/2,4-$\sqrt{-48}$/2