Question

Zerosn of the quadritic polynomia x²+13x+36

Answer 1

Answer:

I HOPE THIS IS THE TRUE ANSWER

Answer 2

QUESTION:

${x}^{2} + 13x + 36$

find the zeroes of the polynomial.

ANSWER:

QUADRATIC equation is in the form of

$a {x}^{2} + bx + c = 0$

Splitting the middle term;

we have to split the middle term in such a way that it's sum equal to b i.e 13and product equal to a × c that is 36.

${x}^{2} + 9x + 4x + 36$

taking common factor

$x(x + 9) + 4(x + 9)$

$(x + 9)(x + 4)$

are the zeroes.

FINAL ANSWER :

$x = -9 or - 4$

are the zeroes of the polynomial .

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