zi = 3-2i..what is the inverse of 2i
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Answer:
2−5i
3+2i
+
2+5i
3−2i
=
(2−5i)(2+5i)
(3+2i)(2+5i)+(3−2i)(2−5i)
=
4+25
−4+19i+(−4−19i)
=
29
−8
Step-by-step explanation:
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