Question

Zinc and hydrochloric acid react according to the reaction
Zn(s) + 2HCl(aq) → ZnCl(aq) + H2(g)
If 0.40 mol Zn are added to hydrochloric acid containing 0.62 mol HCl, how many moles of H, are produced
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Answer 1

1 mole Zn reacts with 2 moles HCl

0.4 mole Zn reacts with 0.8 moles HCl

>>But 0.8 moles HCl is not available so HCl is limiting reagent, HCl will decide the quantity

2 moles HCl reacts with 1 mole Zn

0.62 moles HCl reacts with 0.31 mole Zn

1 mole Zn gives 1 mole H2

0.31 mole Zn gives 0.31 mole H2

>>0.31 moles H2 <--------Answer

Answer 2

Answer:

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Explanation:

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