zinc dissolves in excessof naoh forming
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HEYA HERE,
The zincate ion is formed, as follows:
Zn(OH)2 + 2OH- (from the NaOH) → [Zn(OH)4]2-
More about zinc hydroxide, including that reaction:
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The zincate ion is formed, as follows:
Zn(OH)2 + 2OH- (from the NaOH) → [Zn(OH)4]2-
More about zinc hydroxide, including that reaction:
HOPE IT HELPS PLS MARK ME AS BRAINLIEST
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Zinc react with sodium hydroxide to produce zincate sodium and hydrogen.
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