zinc granules are heated with dilute sulphuric acid in a breaker, a)name the gas liberated. b) how do you test and confirm the gas so liberated? c)write the balanced chemical reaction for this reaction. d) name the type of reaction.
Answers
Answer:
i) Zinc reacts with dilute sulphuric acid(H
2
SO
4
) to form zinc sulphate (ZnSO
4
) and hydrogen(H
2
) gas.
Zn(s)+H
2
SO
4
(aq)→ZnSO
4
(aq)+H
2
(g)
ii) Zinc reacts with hydrochloric acid to form zinc chloride(ZnCl
2
) and hydrogen(H
2
) gas.
Zn(s)+2HCl(aq)→ZnCl
2
(aq)+H
2
(g)
iii) Zinc reacts with sodium hydroxide to form sodium zincate(Na
2
ZnO
2
) and hydrogen(H
2
).
Zn(s)+2NaOH(aq)→Na
2
ZnO
2
(aq)+H
2
(g)
Explanation:
➡ Zinc granules are heated with dilute sulphuric acid in a breaker.
a) Name the gas liberated.
b) How do you test and confirm the gas so liberated ?
c) Write the balanced chemical reaction for this reaction.
d) Name the type of reaction.
☯ When zinc granules are heated with dilute sulphuric acid to form zinc sulphate with liberation of hydrogen gas .
a) Hydrogen gas is liberated .
b) The given gas can be tested by bringing a flame nearby the test containing the gas , if it burns with a pop sound , presence of hyrogen is confirmed .
c)
d) Type of reaction - Displacement Reaction