Question

zinc sulphide + oxygen gives rise to zinc oxide + Sulphur Dioxide balance this equation

Answer 1

Balanced equation for formation of zinc and sulfur dioxide due to reaction of zinc sulfide and oxygen.

Explanation:

• In the given reaction, the reactant are zinc sulfide (Zns) and Oxygen whereas the products are zinc oxide (ZnO) and sulfur dioxide.
• The chemical equation involved in this reaction is as follows:

$ZnS+O_2\rightarrow ZnO+SO_2$

• An equation is considered to be balanced only when it has the atoms involved in reaction in both the reactant part as well as the product part are same.
• When the above-given equation is examined, on the reactant side it has 1 atom of Zn, 1 atom of S and 2 atoms of O whereas on the product side it has 1 atom of Zn, 1 atom of S and 3 atoms of O.
• As the values of oxygen are not the same in both side, the above given reaction is not balanced.
• Thus to make it balanced, some changes as shown in the following balanced equation is done

$2ZnS+3O_2\rightarrow 2ZnO+2SO_2$

• When the above equation is examined, on the reactant side it has 2 atoms of Zn, 2 atoms of S and 6 atoms of O, whereas on the product side it has atoms of Zn, 2 atoms of S and 6 atoms of O.

• As both side are equal the balanced chemical equation for the reaction given is

$2ZnS+3O_2\rightarrow 2ZnO+2SO_2$

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Answer 2

Answer:

2ZnS + 3O2 = 2 ZnO + 2 SO2

Hope it helps you..