zinc tetraoxosulphate (vi) solution was electrolysed in such a way that 0.5 amp flowed for 32 minutes 10 seconds,depositing 0.325g of zinc at the cathode. calculate the number of moles of zinc deposited
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1.Calculate the volume of oxygen liberated at 28oC and 770mmHg when Gold (III)trioxonitrate (v) solution between platinum electrodes, if 7.5g of gold wasdeposited at the cathode. [Au = 197, Gas molar volume at s.t.p.22.4 dm3]2. Zinc tetraoxosulphate (VI) solution was electrolyzed in such a way that 0.5Aflowed for 32 minutes 10 seconds, depositing 0.325g of zinc at the cathode.Calculate:(i) the no. of moles of zinc deposited;(ii) the no. of coulomb of electricity required to deposit 1 mole of Zn.(iii) the charge on a zinc ion[Zn = 65, 1 Faraday= 96500 C]3.Exactly 0.4 faraday electric charge is passed through three electrolytic cells inseries, first containing AgNO3, second CuSO4and third FeCl3solution. How manygram of each metal will be deposited assuming only cathodic reaction in eachcell? [Ag = 108; Cu = 63.5; Fe = 56]