ZM18, VQ21, RU27, NY39 what is next value
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2
Answer:
ur answer is JC63
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Answered by
0
Answer:
We should find the sequence between each terms in the given series.
Final Answer: ZM18, VQ21, RU27, NY39, JC63
Step-by-step explanation:
From the given question,
Alphabets: A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Take the first term(ZM18).
- Step 1: Consider the first value.That is Z.To find the first value of second term in the series, the alphabets should consider in the backword counting.
- That is, Z - 4 = V => First value of second term
- Step 2: Now consider the second value of first term.That is M.To find the second value of second term in the series, the alphabets should consider in the forward counting.
- That is, M + 4 = Q => Second value of second term
- Step 3: Consider the third value.That is 18.To find the third value of second term in the series, third value should add with 3.
- That is, 18 + 3 = 21 => Third value of second term
- Second term: VQ21
Similarly we should do the above three steps for the next terms in the series.
Take second term(VQ21)
- Step 1: V - 4 = R
- Step 2: Q + 4 = U
- Step 3: 21 + 6 = 27
- Third term: RU27
Take third term(RU27)
- Step 1: R - 4 = N
- Step 2: U + 4 = Y
- Step 3: 27 + 12 = 39
- Fourth term: NY39
Take fourth term(NY39)
- Step 1: N - 4 = J
- Step 2: Y + 4 = C
- Step 3: 39 + 24 = 63
- Fifth term: JC63
Final Answer:ZM18, VQ21, RU27, NY39, JC63
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