Chemistry, asked by unsee16, 3 months ago

zn + 2Hcl gives us zncl2 +H2۔calculate the volume of hydrogen gas liberated at STP when 32.65g of zinc react with HCL

Answers

Answered by 042000yashijha
0

Answer:

11.2 LITRES

Explanation:

givan that mass of zinc is 32.65g

molar mass of zinc is 63.5g

so moles of zinc are=32.5/63.5

. 0.5 moles

now from the equation :-

Zn +2HCl––>ZnCl2+H2

We apply unitary method:-

1mol of Zn form 1 mol of H2 so

0.5moles of Zn will form 0.5moles of H2

MOREOVER:-

1 mol contains=22.4L. (at STP)

0.5 moles will contain =22.4 x 0.5

. =11.2L of H2 at STP

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