zn + 2Hcl gives us zncl2 +H2۔calculate the volume of hydrogen gas liberated at STP when 32.65g of zinc react with HCL
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Answer:
11.2 LITRES
Explanation:
givan that mass of zinc is 32.65g
molar mass of zinc is 63.5g
so moles of zinc are=32.5/63.5
. 0.5 moles
now from the equation :-
Zn +2HCl––>ZnCl2+H2
We apply unitary method:-
1mol of Zn form 1 mol of H2 so
0.5moles of Zn will form 0.5moles of H2
MOREOVER:-
1 mol contains=22.4L. (at STP)
0.5 moles will contain =22.4 x 0.5
. =11.2L of H2 at STP
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