Zn + 2HCl -> ZnCl2 +H2 Calculate the volume of H2 gas liberated of STP when 32.65 gn of Zn reacts with HCl. 1 mol of gas occupies 22.7 litre volume of S.T.P. (At mass of Zn 65.34)
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Answer:
Balanced reaction is:
Zn+2HCl→ZnCl2+H2
Molar mass of Zn= 65.4 g/mol
thus 65.4 g of zinc liberates 1 mol i.e. 22.4 L hydrogen gas at STP
32.65 g of zinc will liberate: 65.422.4×32.65=11.18L of hydrogen gas at STP
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