Question

Zn and hydrochloric acid react according to the reaction, Zn(s) + 2HCl(aq) → ZnCl2 (aq) + H2(g) If 0.30 mol Zn are added to HCl containing 0.52 mol of HCl how many moles of H2 are produced?​

Answer 1

Answer:

Zn(s)+2HCl(aq.)→ZnCl

2

(aq.)+H

2

(g)

Initial moles 0.30 0.52 0 0

Final moles 0.04 0 0 0.26

∵ Mole ratio of Zn:HCl:H

2

is 1:2:1

∴ Moles of H

2

formed =0.26

Note that HCl is used completely and thus it is limiting reagent.

Explanation:

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