Question

zn==> znO
balance equation in basic medium



Answer please right

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Answer 1

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}⋆$

Answer:−

$\tt{Zn \longrightarrow ZnO}Zn⟶ZnO$

This is a basic medium and the equation is half redox reaction.

This is basically an oxidation reaction, as An is oxidised.

Now, to balance it we will use ion electron method to balance the equation.

Step 1 :- To write the charges.

$\tt{{Zn}^{0} \longrightarrow {({Zn}^{+2}{O}^{-2})}^{0}}Zn </p><p>0$

⟶(Zn

+2

O

−2

)

0

Step 2 :- To balance Oxygen

$\tt{Zn + OH \longrightarrow ZnO}Zn+OH⟶ZnO$

Step 3 :- To balance Hydrogen

$\tt{Zn + 2OH\longrightarrow ZnO + H_2O}Zn+2OH⟶ZnO+H$

2

O

Step 4 :- To check the total charge on both the side

$\tt{{Zn}^{0} + {(2OH)}^{-2}\longrightarrow {({Zn}^{+2}{O}^{-2})}^{0} + {H_2O}^{0}}Zn$

0

+(2OH)

−2

⟶(Zn

+2

O

−2

)

0

+H

2

O

0

Now, we can see that on left side there is (-2) charge where as on right side we have 0 charge, so we need to balance it.

Step 5 :- To balance charges on both the side

For that we need to add (2e-) on the right side to eliminate the positive charge there.

$\tt{{Zn}^{0} + {(2OH)}^{-2} \longrightarrow {({Zn}^{+2}{O}^{-2})}^{0} + {(H_2O)}^{0} + 2{e}^{-}}Zn$

0

+(2OH)

−2

⟶(Zn

+2

O

−2

)

0

+(H

2

O)

0

+2e

−

So, the final balanced equation is:-

$\huge\bf{\boxed{\pink{\tt{Zn + 2OH \longrightarrow ZnO + H_2O+ 2{e}^{-}}}}}$

Zn+2OH⟶ZnO+H

2

O+2e

−

Answer 2

Lol zn is zinc and Zno is zinc oxide
Zno (2)