Question

Zn+NaNo3 NaOH =Na2Zno2+NH3+H2O balance chemical equation by oxidation number​

Answer 1

Answer:

This is an oxidation-reduction (redox) reaction:

4 Zn0 - 8 e- → 4 ZnII

(oxidation)

NV + 8 e- → N-III

(reduction)

Zn is a reducing agent, NaNO3 is an oxidizing agent.

Answer 2

Zn + 3NaNO3 + 6NaOH → Na2ZnO2 + 6NH3 + H2O

Zn+NaNo3 NaOH =Na2Zno2+NH3+H2O balance chemical equation by oxidation number​ is Zn + 3NaNO3 + 6NaOH → Na2ZnO2 + 6NH3 + H2O.

• We must first ascertain the oxidation statuses of each component in the reaction to balance the chemical equation using oxidation numbers:

Zn + NaNO3 + NaOH → Na2ZnO2 + NH3 + H2O

Zn: 0

Na: +1

N: +5

O: -2

H: +1

• Using these oxidation states, we can see that the following changes occur:

Zn is oxidized from 0 to +2

N is reduced from +5 to -3

O is reduced from -2 to -1

• To balance the equation, we can follow these steps:

• Balance the zinc atoms by adding a coefficient of 1 to Zn and 1 to Na2ZnO2:

• Zn + NaNO3 + NaOH → Na2ZnO2 + NH3 + H2O

• Balance the nitrogen atoms by adding a coefficient of 6 to NH3:

• Zn + NaNO3 + NaOH → Na2ZnO2 + 6NH3 + H2O
• Balance the hydrogen atoms by adding a coefficient of 6 to NaOH:
• Zn + NaNO3 + 6NaOH → Na2ZnO2 + 6NH3 + H2O
• Balance the oxygen atoms by adding a coefficient of 3 to NaNO3 and 1 to H2O:
• Zn + 3NaNO3 + 6NaOH → Na2ZnO2 + 6NH3 + H2O
• The final balanced chemical equation by oxidation number is:
• Zn + 3NaNO3 + 6NaOH → Na2ZnO2 + 6NH3 + H2O

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