Question

Zn(OH)2 +4NH4OH (excess) 4X + Y 1. Product X is H20 and Y is [Zn(NH3)4SO4 2. Product X is H20 and Y is [Zn(NH3)4](OH)2 3. Product X is H20 and Y is [Zn(NH2)4(OH)2 4. Product X is H20 and Y is [Zn(NH2)4SO4 ​

Answer 1

Answer:

:)

Explanation:

Zn(OH)2 +4NH4OH (excess) 4X + Y 1. Product X is H20 and Y is [Zn(NH3)4SO4 2. Product X is H20 and Y is [Zn(NH3)4](OH)2 3. Product X is H20 and Y is [Zn(NH2)4(OH)2 4. Product X is H20 and Y is [Zn(NH2)4SO4

Answer 2

The correct option is 2.

The correct option is 2.Product X is $H_2O$ and Y is $[Zn(NH_3)_4](OH) _2$ .

• Zinc hydroxide is a amphoteric substance. When zinc hydroxide reacts with excess ammonium hydroxide it gives 4 moles of water along with a amonium complex named as tetramminezinc(II) hydroxide.
• The reaction is -

$Zn(OH) _2+NH_4OH\rightarrow [Zn(NH_3)_4](OH) _2+4H_2O$