Zn(s) + 2HCl (aq) → ZnCl2 (aq) + H2
3. What is the limitation of the reaction
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Answer:
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Explanation:
Hence, HCl will be the limiting reagent in the reaction and Zn will be excess reagent. Amount of hydrogen produced will be = 0.26 moles. Hence, HCl will be the limiting reagent in the reaction and Zn will be excess reagent.
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