Zn | Zn^2+ (C1) || Zn^2+ (C2) | Zn(s) . The ∆G is negative if
(1). C1=C2
(2). C1 greater than C2
(3). C2 greater than C1
(4). C1 greater than 2×C2
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Answer:
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Answer:
(3)C2>C1
Explanation:
Ecell = E⁰ - {0.059/2xlog(Anode/Cathode)}
Ecell = 0 - {0.059/2xlog(C1/C2)
For ∆G to be -ve E should be +ve
E = -0.03x log(C1/C2)
When C2>C1, log (C1/C2) is -ve
Therefore, E becomes +ve (minus x minus = plus)
So ∆G is -ve, ie spontaneous
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