Question

Zn | Zn^2+ (C1) || Zn^2+ (C2) | Zn(s) . The ∆G is negative if
(1). C1=C2
(2). C1 greater than C2
(3). C2 greater than C1
(4). C1 greater than 2×C2

Answer 1

Answer:

this question is too difficult for me to solve

Answer 2

Answer:

(3)C2>C1

Explanation:

Ecell = E⁰ - {0.059/2xlog(Anode/Cathode)}

Ecell = 0 - {0.059/2xlog(C1/C2)

For ∆G to be -ve E should be +ve

E = -0.03x log(C1/C2)

When C2>C1, log (C1/C2) is -ve

Therefore, E becomes +ve (minus x minus = plus)

So ∆G is -ve, ie spontaneous