Question

Zoe is pole-vaulting. At the end of her approach run, she has a horizontal velocity of 8 m/s and her center of gravity is 1.0 m high. If zoe's mass is 50 kg, estimate how high she should be able to vault if her kinetic and potential enrgies are all converted to potential energy

Answer 1

Explanation:

Given an array of positive numbers, find smallest number that cannot be formed with sum of numbers from an array

Answer 2

Zoe should be able to reach 4.27 m height

Explanation:

The kinetic energy is given as

$K=\frac{1}{2} mv2$

Here, m is the mass of the Zoe and v is the velocity of her.

Given m =50 kg and v = 8 m/s.

so,

$K=\frac{1}{2}50kg\times(8m/s)^2$

K = 1600 J.

as zoe's center of gravity is 1.0 m high, so potential energy

$U_{initial} = mgh$

$U_{initial} = 50 kg\times9.8m/s^2\times 1.0 m.$

             =  490 J.

since total energy converted in PE,  

Total energy,E =  1600 J + 490 J

                      E = 2090 J

Therefore,

$E=U_{final} =mgH$

substitute the value, we get

$2090J=50kg\times9.8m/s^2\times H$

H = 4.265 m

Thus, Zoe should be able to reach 4.27 m height.

#Learn More: total energy.

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