Zoology
Question No. 1
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The temperature of a gas at pressure 2 atm and volume 2 L is 127°C. Keeping its volume constant if its temperature is raised to 927°C, then its new pressure will be
6 atm
Answers
Question - The temperature of a gas at pressure 2 atm and volume 2 Lis 127°C Kooping its volume constant if its temperature is raised to 927°C, then its new
pressure will be
O 6 atm
o 4 atm
O2 atm
0 1 atm
Given - Original pressure : 2 atm
Original temperature : 127°C
Constant volume : 2 litre
New temperature : 927°C
Find - New pressure in the condition of constant volume.
Solution - The final pressure will be calculated as per the Ideal Gas Law, PV = nRT, where p is pressure, v is volume, n is number of moles, R is gas constant and T is temperature.
Converting temperature in Kelvin -
Original temperature : 127 + 273 = 400 K
New temperature : 927 + 273 = 1200 K
Now relating the given conditions, P1/T1 = P2/T2.
Keeping the values in equation-
2/400 = P2/1200
P2 = 2*1200/400
P2 = 6 atm.
Thus, new pressure will be : 6 atm.