Question

Zubin factorized the algebraic expression 20x2 + 5xy2 – 25xyz as given below. In which step
did he make the first mistake?

Step 1: 5 x 2 x 2 x x x x + 5 x x x y xy-5 5 x x x y z

Step 2: 5 x x(2 x 2 x x + y xy-5xy X z)

Step 3: 5x(4x + y2 – 5yz)

(A) Step 1
(B) Step 2
(C) Step 3
(D) All the steps are correct​

Answer 1

Solution :-

→ 20x² + 5xy² – 25xyz

step 1) of Zubin :- 5 * 2 * 2 * x * x + 5 * x * y * y - 5 * 5 * x * y * z

• correct .

step 2) of Zubin :- 5x * (2 * 2 * x + y * y - 5xy * z)

• wrong .

correct one should taking 5x common we get,

• 5x(2 * 2 * x + y * y - 5 * y * z)

step 3) of Zubin :- 5x(4x + y² - 5yz) .

• correct .

therefore, we can conclude that, Zubin made mistake in second step.

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Answer 2

Given : Zubin factorized the algebraic expression 20x² + 5xy² – 25xyz as below"

5*2*2*x*x + 5*x*y*y  - 5*5*x*y*z

5x(2*2*x + y*y  - 5  y*z )

= 5x(4x + y² - 5yz)

To Find :  In which step did he make the first mistake?

(A) Step 1

(B) Step 2

(C) Step 3

(D) All the steps are correct​

Solution

algebraic expression 20x² + 5xy² – 25xyz as

Step 1:    5*2*2*x*x + 5*x*y*y  - 5*5*x*y*z

Step 2 :  5x(2*2*x + y*y  - 5  y*z )

Step 3 :  5x(4x + y² - 5yz)    

20x² + 5xy² – 25xyz  = 5x(4x + y² - 5yz)    

All steps are correct

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