Zul and Amelia have a baby daughter, Shanise. Zul is 23 kg heavier than Amelia,who is four times heavier than shanise.Their combined weight is 122kg.How heavy is each person?
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Answered by
4
==>Weight in Kg
Let Zul's weight be q
Let Amelia's weight be w
Let Shanise's weight be v
Given :
1. q=w+23
2. w=4v
3. q+w+v = 122
Firstly, take w=4v
v=w/4
Substitute eqn no. 1 and 2 in 3
w+23+ w+w/4=122
w/4=99-2w
Multiply both sides by 4
w= 396-8w
9w=396
w=44
q= w+23
q= 44+23
q=67
v = w/4
v=44/4
v=11
Therefore,
q+w+v = 122
67+44+11=122
122=122
#Happy_Learning!
Let Zul's weight be q
Let Amelia's weight be w
Let Shanise's weight be v
Given :
1. q=w+23
2. w=4v
3. q+w+v = 122
Firstly, take w=4v
v=w/4
Substitute eqn no. 1 and 2 in 3
w+23+ w+w/4=122
w/4=99-2w
Multiply both sides by 4
w= 396-8w
9w=396
w=44
q= w+23
q= 44+23
q=67
v = w/4
v=44/4
v=11
Therefore,
q+w+v = 122
67+44+11=122
122=122
#Happy_Learning!
Answered by
0
Answer:
Step-by-step explanation:
x+4x4x+23
9x+23=122
122-23=99
9/99=11
j=67
A=44
S=11
11+44+67=122 kg
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