Question

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Answer 1

SOLUTION

Option (c)✓✓

Refer to the attachment.

hope it helps ☺️

Answer 2

Explanation:

Given that

Volume (v) = 10 lit

T = 300k

Total pressure P = 2 atm

R = 0.0821 L atm mol^-1 K ^-1

PV = n R T

n = PV/RT

n = (2 × 10)/0.0821 × 300

n = 20/24.63

n = 0.812

Number of moles of C02 = ( 0.812 - 0.2)

= 0.612 moles

Partial pressure of CO2 = (0.612×2)/0.812

= 1.51 atm