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lonerangerkapip2y5ii:
Yash give me your phone no .
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Hii friend,
Here is your answer,
The moment of inertia of a uniform rod (I) = ML^2/12,
Now since,
I = MK^2 (K = radius of gyration)
Therefore,
=> ML^2/12 = MK^2
=> K^2 = L^2/12
=> K = L/√12
Thus the radius of gyration of a uniform rod is L/√12.
Hope it helps you.
Thank you
Here is your answer,
The moment of inertia of a uniform rod (I) = ML^2/12,
Now since,
I = MK^2 (K = radius of gyration)
Therefore,
=> ML^2/12 = MK^2
=> K^2 = L^2/12
=> K = L/√12
Thus the radius of gyration of a uniform rod is L/√12.
Hope it helps you.
Thank you
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