3. Three times of a number added to two times of another number gives 33. When three times of the second number is subtracted from four times the other number got 10. taking the numbers as x and y form the equations and find the numbers?
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Answer:
x=6 and y=7
Step-by-step explanation:
three times of y is 21 and two times of x is 12 total we got is 21+12=33
three times of x=18 and four times od y=28
when we substract 4y-3x=10
same as that 28-18=10
hence the value of x and y is 6 and 7 respectively
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