Question

ପ୍ରକାଶି ' ଶବ୍ଦର ଅର୍ଥ ଲେଖ ।​

Answer 1

Answer:

The cost of fencing a circular field at the rate of rs 24 per metre is rs 5280.

The field is to be ploughed at the rate of rs 0.50 per m^2.

To find:-

The cost of ploughing the field.

______________________________

Length of the fence (in metres) = Total cost/Rate = 5280/24 = 220

As we know, the circumference of the field = 220 m

If r metres is the radius of the field, then 2πr = 220

2 × (22/7) × r = 220

r = (220 × 7)/ (2 × 22)

r = 35

Hence, the radius of the field = 35 m

Area of the field = πr^2

= (22/7) × 35 × 35

= 22 × 5 × 35 m^2

Cost of ploughing 1 m^2 of the field = Rs. 0.50

So, total cost of ploughing the field = 22 × 5 × 35 × Rs. 0.50 = Rs. 1925

Answer 2

Explanation:

${ {3}^{2} }^{3}  \times  {(2 \times  {3}^{5}) }^{ - 2}  \times  {18}^{2 }  \\  \\  =  {3}^{6}  \times  \frac{1}{4 \times  {3}^{10} }  \times  {18}^{2}  \\  \\  =  \frac{ {18}^{2} }{4 \times  {3}^{4} }  \\  \\  =  \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}}  \: ^{ \cancel{6 }} \:  ^{ \cancel{2}} \:  ^1 }{ { \cancel{4 }\:_1}\times { \cancel{3} \: _1} \times { \cancel{3 } \: _1}\times { \cancel{3} \:_1} \times { \cancel{3} \: _1} }  \\  \\  = { \huge{ \red{ \boxed{1}}}}$