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Answer:
❍ Let assume as the age of son six years before be x respectively.
Then, Mother's age is x².
And,
Present age of son be (x + 6)
Present age of Mother's be (x² + 6).
— After three years, their ages;
Son's age is (x + 3 + 6) = (x + 9)
Mother's age is (x² + 3 + 6) = (x² + 9).
⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀
\qquad\quad{\underline{ \underline{ \purple{\bigstar\:\frak{According \: to \: the \: Given \: Question :}}}}}
★AccordingtotheGivenQuestion:
Three years hence, the mother's age will be thrice the age of her son.
Mother's age = 3(son's age)
Therefore,
\begin{gathered}:\implies\sf x^2 + 9 = 3(x + 9) \\\\\\:\implies\sf x^2 + 9 = 3x + 27 \\\\\\:\implies\sf x^2 - 3x + 9 - 27 = 0 \\\\\\:\implies\sf x^2 - 3x - 18 = 0 \\\\\\:\implies\sf x^2 - 6x + 3x - 18 = 0 \\\\\\:\implies\sf x(x - 6) + 3(x - 6) = 0 \\\\\\:\implies\sf (x - 6) \; or \; (x + 3) = 0 \\\\\\:\implies{\underline{\boxed{\frak{\purple{x = 6\;or\;-3}}}}}\;\bigstar\end{gathered}
:⟹x
2
+9=3(x+9)
:⟹x
2
+9=3x+27
:⟹x
2
−3x+9−27=0
:⟹x
2
−3x−18=0
:⟹x
2
−6x+3x−18=0
:⟹x(x−6)+3(x−6)=0
:⟹(x−6)or(x+3)=0
:⟹
x=6or−3
★
⠀⠀
By ignoring –ve value(-3). Because, Age can't be negative. Taking Positive value of, x = 6.
Hence,
Present age of Son is, (x + 6) = (6 + 6) = 12 years.
Present age of Mother is, (x ² + 6) = (6² + 6) = (36 + 6) = 42 years.
⠀⠀
\therefore{\underline{\sf{Hence, \; present\; ages\:of\;son\; and\;mother\:are\;\frak{12\;\&\;42\;years.}}}}∴
Hence,presentagesofsonandmotherare12&42years.
Answer:
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