Question

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Answer 1

2 - digit numbers that leave remainder 1 when divided by 5 are: 11, 16, 21... 96.

First-term a = 11 

Common difference d = 5

Last term l = 96.

We know that tn = a + (n - 1)  * d

= > 96 = 11 + (n - 1) * 5

= > 96 = 11 + 5n - 5

= > 96 = 6 + 5n

= > 96 - 6 = 5n

= > 90 = 5n

= > n = 18.


There 2-digit natural numbers divided by 5 leaves remainder 1 = 18.


Hope this helps!

Answer 2

26÷5=5
remainder=1
I hope it helps