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p ( x ) = 3x² - 4x + 1 , Then , a = 3 , b = -4 , c = 1
Now , if the zeros of the polynomial are α and β
Then , αβ = c / a = 1 / 3
And , α + β = - b / a = 4 / 3
Therefore ,
α² / β + β² / α
= α³ + β³ / αβ
= ( α + β )³ - 3αβ ( α + β ) / αβ
= [ ( 4 / 3 )³ - 3 × 1 / 3 × 4 / 3 ] / [ 1 / 3 ]
= [ 64 / 27 - 4 / 3 ] / [ 1 / 3 ]
= [ 64 - 36 / 27 ] / [ 1 / 3 ]
= 28 / 27 × 3
= 28 / 9
And ,
α² / β × β² / α
= αβ
= 1 / 3
•°• The polynomial will be ,
p ( x ) = x² - ( α² / β + β² / α )x + ( α² / β × β² / α )
= x² - 28x / 9 + 1 / 3 [ • Required answer ]
________________
Thanks!
__________________________
p ( x ) = 3x² - 4x + 1 , Then , a = 3 , b = -4 , c = 1
Now , if the zeros of the polynomial are α and β
Then , αβ = c / a = 1 / 3
And , α + β = - b / a = 4 / 3
Therefore ,
α² / β + β² / α
= α³ + β³ / αβ
= ( α + β )³ - 3αβ ( α + β ) / αβ
= [ ( 4 / 3 )³ - 3 × 1 / 3 × 4 / 3 ] / [ 1 / 3 ]
= [ 64 / 27 - 4 / 3 ] / [ 1 / 3 ]
= [ 64 - 36 / 27 ] / [ 1 / 3 ]
= 28 / 27 × 3
= 28 / 9
And ,
α² / β × β² / α
= αβ
= 1 / 3
•°• The polynomial will be ,
p ( x ) = x² - ( α² / β + β² / α )x + ( α² / β × β² / α )
= x² - 28x / 9 + 1 / 3 [ • Required answer ]
________________
Thanks!
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