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Odd numbers are of the form 2q + 1
Let x = 2m + 1
y = 2n + 1
Now,
x²+y²
=( 2m + 1)² + (2n + 1)²
= 4m² + 4m + 1 + 4n² + 4n + 1
= 4m² + 4n² + 4m + 4n + 2
= 4 (m² + n² + m + n) + 2
= 4 k + 2 ,(where k = m²+n²+m+n)
It is a even number but not divisible by 4 since it has remainder 2
tamanna4260:
we can let x and y for any odd integer?
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