0-0=2 how answer came 2
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Answered by
18
Hey, your answer is given below.
Firstly, 0 - 0 = 2 is never possible other than doing some errors!
Here, it is!
Let, a = 1
⇒ a × a = 1 × a, multiplying both sides by a
⇒ a² = a
⇒ a² - 1 = a - 1, subtracting 1 from both sides
⇒ (a + 1) (a - 1) = (a - 1)
⇒ a + 1 = 1, multiplying both sides by inverse of (a - 1)
⇒ a + 1 = 1
⇒ a + 1 - 1 = 1 - 1, subtracting 1 from both sides
⇒ a = 0
⇒ 1 = 0, since a = 1
Now, 0 - 0
= 1 - 1
= 1² - 1²
= (1 + 1) (1 - 1)
= 2 × 0, since 1 - 1 = 0
= 2 × 1, since 1 = 0 as proved earlier
= 2
Hence, 0 - 0 = 2 [Proved]
It is not possible! Though 0/0 is indeterminate form, we have taken that as defined to solve the problem.
Hope it helps you!
Firstly, 0 - 0 = 2 is never possible other than doing some errors!
Here, it is!
Let, a = 1
⇒ a × a = 1 × a, multiplying both sides by a
⇒ a² = a
⇒ a² - 1 = a - 1, subtracting 1 from both sides
⇒ (a + 1) (a - 1) = (a - 1)
⇒ a + 1 = 1, multiplying both sides by inverse of (a - 1)
⇒ a + 1 = 1
⇒ a + 1 - 1 = 1 - 1, subtracting 1 from both sides
⇒ a = 0
⇒ 1 = 0, since a = 1
Now, 0 - 0
= 1 - 1
= 1² - 1²
= (1 + 1) (1 - 1)
= 2 × 0, since 1 - 1 = 0
= 2 × 1, since 1 = 0 as proved earlier
= 2
Hence, 0 - 0 = 2 [Proved]
It is not possible! Though 0/0 is indeterminate form, we have taken that as defined to solve the problem.
Hope it helps you!
Steph0303:
:v: Grt answer
Answered by
9
hey there!
We know that ,
0 = 0
Now,
0² - 0² = 0
( 0 + 0 ) ( 0 - 0 ) = 2 ( 0 )
( 0 + 0 ) ( 0 - 0 ) = 2(0 + 0 )
( 0 - 0 ) = 2 .
This is not a actually true, but we will prove it somehow. Here, ( 0 - 0 ) / ( 0 - 0) = not defined, But here we cancelled them.
Hope helped!
We know that ,
0 = 0
Now,
0² - 0² = 0
( 0 + 0 ) ( 0 - 0 ) = 2 ( 0 )
( 0 + 0 ) ( 0 - 0 ) = 2(0 + 0 )
( 0 - 0 ) = 2 .
This is not a actually true, but we will prove it somehow. Here, ( 0 - 0 ) / ( 0 - 0) = not defined, But here we cancelled them.
Hope helped!
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