Question

0.0001 M HCl विलयन का pH मान है ?​

Answer 1

$ph = - log_{}(h {}^{ + } )$

in this case

$h {}^{ + } = 10 {}^{ - 4}$

then,

$ph = - log(10 {}^{ - 4} )$

$= 4 log(10)$

we know ,

$log(10) = 1$

then ,

$ph = 4$

⏩I hope it help you