0.001 mol of cr(NH3), (NO3) So4 was passed on
Cataion exchanger and the held coming out
of it required 20 mol of 0.1 molar NaoH for
Nutrilisation. Hence the complex is.
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1
Answer:
The complex is [CoNO
3
(NH
3
)
5
]SO
4
.
1molNaOH
0.020L×0.1mol/LNaOH×1molacid
=0.0020molacid
10
−3
mol
0.0020mol
=2
As 2 moles of acid in the exchanger replaced each 1 mole of complex cations, so the complex must have an oxidation state of +2, so the complex will be [CoNO
3
(NH
3
)
5
]SO
4
.
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