Question

0.005M acid solution has 5 pH. The percentage ionization of acid is 1) 0.8% 2) 0.6% 3) 0.4% 4) 0.2%

Answer 1

Answer:

0.2%.

[H+]=10-ph=10-5

a=actual concentration/molar concentration=10-5/0.005

=0.2×10-2

therefore,%composition=0.2×10-2×100

=0.2%