Question

If α and β are the zeroes of the quadratic polynomial

f(t) = t2 – 4t + 3, find the value of α4β3 + α3β4.​

Answer 1

Step-by-step explanation:

Since, α and β are the zeroes of the quadratic polynomial f(t) = t2 – 4t + 3

So, Sum of the zeroes = α + β = 4

Product of the zeroes = α × β = 3

Now,

α4β3 + α3β4 = α3β3(α + β)

= (3)3(4) = 108

HENCE, U GOT UR ANSWER....

Answer 2

we know


alpha and beta are the zeroes of the given quadratic equation. so

Sum of the zeroes = alpha + beta= 4

Product of the zeroes = alpha × beta = 3

Now we have


A4B3 + A3B4 = A3B3 ( A + B)

(3) 3 (4) = 108.


HOPE IT HELPS.