Question

0.01 m solutions of NaCl and MgCl2 are

prepared in water. The boiling point of NaCl

solution is found to be 378 K. What is the

boiling point of MgCl2 solution under identical

conditions of temperature and pressure?

(consider 373 K as boiling point of pure water)​

Answer 1

Answer:

380.5

Explanation:

tb=i*kf*m

5=2*kf*0.01

kf=250

put this for Mgcl2

tb=i*kf*m

tb= 3*250*0.01

tb=7.5

hence boiling point=373+7.5

bp= 380.5