Question

0.01 moles 300ml naoh,0.02moles 200ml of KOH and 0.05 moles 100ml HCL? ​

Answer 1

Answer:

1 M H

2

SO

4

solutio has 2M H

+

ions

Therefore, moles of H

+

in:

200 ml of 1M H

2

SO

4

= 2×0.2L×1mol/L=0.4

300 ml 0f 3M HCl = 0.3L×3mol/L=0.9

100 ml 0f 2M HCl = 0.1L×2mol/L=0.2=1.5

Total volume = 1L

So [H

+

] = 1.5 mol/L

Explanation:

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