Question

0.0833 mole of carbohydrate of empirical formula ch2o contain 1 gram of hydrogen the molecular formula of carbohydrate is​

Answer 1

Answer: The molecular formula for the given carbohydrate will be $C_6H_{12}O_6$

Explanation:

We are given:

Empirical formula for a carbohydrate = $CH_2O$.

The general formula for carbohydrate can be written as $(CH_2O)_n$

By Stoichiometry of the compound:

1 mole of a carbohydrate contains $2n\times 1g=(2n)g$ of hydrogen atom.

So, 0.0833 mole of carbohydrate will contain $\frac{2n}{1}\times 0.0833=0.1666n$ grams of hydrogen atom.

Also, mass of hydrogen in 0.0833 moles is given to be 1 g

ram.

By equating both the quantities, we get:  

$0.1666\times n=1\\n=6$

Hence, the molecular formula for carbohydrate will be $(CH_2O)_6=C_6H_{12}O_6$