A particle of mass 0.3 kg is subjected to a force F = −kx with k = 15 N/m. What will be its initial acceleration if it is released from a point x = 20 cm?
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15
f =-kx
ma=-kx
0.3a=15*0.2
a= 15*2/3
a=10m/s²
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5
Answer:
The initial acceleration when the particle is released from a point x = 20 cm is 10 m/s².
Explanation:
Displacement of the particle from the mean position, x = 20 cm = 0.2 m
k = 15 N/m
Mass of the particle, m = 0.3 kg
Acceleration,
a=F/m
⇒a=kx/m=15(0.2)/0.3
=3/0.3
=10 m/s²
So, the initial acceleration when the particle is released from a point x = 20 cm is 10 m/s².
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