Question

0.1*0.1*0.1+0.01*0.01*0.01/.2*.2*.2+.2*.2*.2

Answer 1

$\frac{0.1 \times 0.1 \times 0.1 + 0.01 \times 0.01 \times 0.01}{0.2 \times 0.2 \times 0.2 + 0.2 \times 0.2 \times 0.2} \\ \\ \\ = 0.001 + 0.000001 \div \: 0.008 + 0.008 \\ \\ \\ = 0.001001 \div 0.016 \\ \\ \\ \boxed{= 0.0625625}$

Answer 2

$\huge{\bold{\underline{\star\: Solution\: \star}}}$

$a\:= \:0.1 \\b \:=\: 0.01$

c = 0.2

$\frac{a^{3}+b^{3}}{(c^{3} + c^{3})}\\ \frac{ (a+b)(a^{2} -ab+b^{2})}{2(c^{3})}\\ \frac{ (a+b)[(a+b)^{2}-3ab]}{2(c^{3})}$

Put the value as notified:

$\frac{ (a+b)[(a+b)^{2}-3ab]}{2(c^{3})}\\\frac{ (0.1+0.01)[(0.1+0.01)^{2}-3(0.1)(0.01)]}{2(0.2^{3})} \\ \frac{(0.11)[(0.11)^{2} -0.003]}{2(0.08)}\\ \frac{(0.11)[0.0121-0.003]}{0.016}\\ \frac{(0.11)(0.0091)}{0.016}\\ \implies 0.0625$

$\red{\underline{Answer}}$

0.0625