Question

0:1) Find the amount and compound
interest on upees 2000 for years
at rate 5% per annum compounded
annually
​

Answer 1

Answer:

Amount= Principal×(1+r/100)^2

= 2000 × ( 1 + 5/100) (1+5/100)

= 2000 × 105/100 ×105/100

=2×105× 105/10

= 2205

Amount= ₹2205

CI = 2205-2000 = ₹205

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Correct Question:-

Find the amount and compound interest on rupees 2000 for 2 years at rate 5% per annum compounded annually

$\bf{\underline{\underline\red{Given:-}}}$

• Principal = Rs. 2000

• Rate = 5%

• Time = 2 years

$\bf{\underline{\underline\blue{To\: Find:-}}}$

• The Amount

• And Compound Interest compounded annually.

$\bf{\underline{\underline\green{Solution:-}}}$

As we know that:-

The formula for finding Amount is:-

$\boxed{ \rm \leadsto Amount = P \bigg(1 + \frac{r}{100} \bigg)^{n} }$

Here:-

• P = Principal = Rs. 2000

• r = rate = 5%

• n = time = 2 years.

Substituting the values:-

$\rm\implies 2000 \bigg(1 + \dfrac{5}{100} \bigg)^{2}$

$\rm\implies 2000 \bigg( \dfrac{100 + 5}{100} \bigg)^{2}$

$\rm\implies 2000 \bigg( \dfrac{105}{100} \bigg)^{2}$

$\rm\implies 2000 \bigg( \dfrac{21}{20} \bigg)^{2}$

$\rm\implies 2000 \times \dfrac{21}{20} \times \dfrac{21}{20}$

$\rm\implies \dfrac{21 \times21 \times 2000}{400}$

$\rm\implies 21\times 21 \times 5$

$\rm\implies 2205$

$\underline{ \boxed{ \pink{\rm\therefore Amount = Rs.2205}}}$

Now:-

The formula for finding the Compound Interest is:-

$\boxed{ {\rm\leadsto Compound \: Interest = Amount - Principal}}$

$\rm = 2205 - 2000$

$\rm = 205$

$\underline{ \boxed{ \purple{\rm\therefore Compound \: Interest= Rs.205}}}$