0.1 g of CO2 occupies a volume of 320 CC at certain conditions. Under similar
conditions 0.2 g of XO2 occupies 440 CC. Calculate the atomic weight of X is
A. 64
B. 32
C. 16
D. 14
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Answer:
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Explanation:
V
1
=320cc=>0.32L;V
2
=440cc=>0.44L;n
1
=
44
0.1
=0.0022;n
2
.
n
1
V
1
=
n
2
V
2
0.0022
0.32
=
n
2
0.44
n
2
=
0.32
0.44∗0.0022
=0.0030
Atomic wt of the element is 'x'
n
2
=
x∗molarmassofdioxide
givenmass
=
x∗32
0.2
0.003=
x∗32
0.2
x=
0.003∗32
0.2
=2.08
therefore the answer is 2.08
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