Question

0.1 g of CO2 occupies a volume of 320 CC at certain conditions. Under similar
conditions 0.2 g of XO2 occupies 440 CC. Calculate the atomic weight of X is
A. 64
B. 32
C. 16
D. 14​

Answer 1

Answer:

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Explanation:

V

1

=320cc=>0.32L;V

2

=440cc=>0.44L;n

1

=

44

0.1

=0.0022;n

2

.

n

1

V

1

=

n

2

V

2

0.0022

0.32

=

n

2

0.44

n

2

=

0.32

0.44∗0.0022

=0.0030

Atomic wt of the element is 'x'

n

2

=

x∗molarmassofdioxide

givenmass

=

x∗32

0.2

0.003=

x∗32

0.2

x=

0.003∗32

0.2

=2.08

therefore the answer is 2.08