Question

0.1 kg body moves at a constant speed of 10 m/s. It is pushed by applying a constant force for 2 sec. Due to this force , it starts moving exactly in the opposite direction with a speed of 4m/s. Then

Answer 1

Answer:

Explanation:

=> Here, 0.1 kg body moves at a constant speed of 10 m/s.

Thus, The initial velocity of the body(u)=10m/S

and Mass of the body=0.1kg

=> It is pushed by applying a constant force for 2 sec.  

Time period=2s

=> Further,  It starts moving exactly in the opposite direction with a speed of 4m/s.  

∴ Finial velocity (v)=-4m/S

now, Change in momentum=10(10-(-4)) = 140

impulse=m×a×t

So, a=impulse÷(m×t)

=140÷(0.1× 2)

= 140÷0.2

=700m/s^2

Thus, the acceleration produced in it is 700m/s^2.