Question

0.1 M HCl (200ml) and 0.1 M NaOH (800ml) was mixed in a container. Concentration of {OH-} ion in the mixture will be?​

Answer 1

Answer:

molarity of HCl is given 0.1

So, number of moles per volume is 0.1 for HCl and it will be same for H+

For the PH part,

PH=log[H+]

=log(0.1). so PH = 1

now we know at 298K P[H+] + P[OH-] = 14

=>P[OH-] = 13

so -log[OH-] = 13

Hence  the answer [OH-] = 10 raised to power of -13(negative 13)

Answer 2

Answer:

Concentration of [OH-] ion in the mixture is 0.1 M.

Explanation:

As morality of NaOH is given which is O.1 M this means concentration that is number of moles per volume is 0.1 for NaOH and same will be for [0H-] ion. We know that NaOH is the strong base and it will completely dissociates into the solution therefore concentration of NaOH will be equal to the concentration of hydroxide ion [OH-] ion which is 0.1M.